x^2-8x=4x-38

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Solution for x^2-8x=4x-38 equation: 



x^2-8x=4x-38

We move all terms to the left:

x^2-8x-(4x-38)=0

We get rid of parentheses

x^2-8x-4x+38=0

We add all the numbers together, and all the variables

x^2-12x+38=0

a = 1; b = -12; c = +38;
Δ = b2-4ac
Δ = -122-4·1·38
Δ = -8
Delta is less than zero, so there is no solution for the equation

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